672=16+16t^2

Solution for 672=16+16t^2 equation:

672=16+16t^2

We move all terms to the left:

672-(16+16t^2)=0

We get rid of parentheses

-16t^2-16+672=0

We add all the numbers together, and all the variables

-16t^2+656=0

a = -16; b = 0; c = +656;
Δ = b2-4ac
Δ = 02-4·(-16)·656
Δ = 41984
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{41984}=\sqrt{1024*41}=\sqrt{1024}*\sqrt{41}=32\sqrt{41}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-32\sqrt{41}}{2*-16}=\frac{0-32\sqrt{41}}{-32}
=-\frac{32\sqrt{41}}{-32}
=-\frac{\sqrt{41}}{-1}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+32\sqrt{41}}{2*-16}=\frac{0+32\sqrt{41}}{-32}
=\frac{32\sqrt{41}}{-32}
=\frac{\sqrt{41}}{-1}
$